use 資料庫
select a.name as 表名,b.name as 欄位名,b.length as 字段長度,c.name 字段型別
from (select * from sysobjects where xtype='u') a join syscolumns b
on a.id=b.id
left join systypes c on b.xusertype=c.xusertype
order by 表名
以下都是異曲同工
select d.name,a.name ,b.name ,a.length, a.isnullable from syscolumns a, systypes b,sysobjects d where a.xtype=b.xusertype and a.id=d.id and d.xtype='u'
這個住處比較詳細不過就比較長
select
(case when a.colorder=1 then d.name else '' end)表名,
a.colorder 字段序號,
a.name 欄位名,
(case when columnproperty( a.id,a.name,'isidentity')=1 then '√'else '' end) 標識,
(case when (select count(*)
from sysobjects
where (name in
(select name
from sysindexes
where (id = a.id) and (indid in
(select indid
from sysindexkeys
where (id = a.id) and (colid in
(select colid
from syscolumns
where (id = a.id) and (name = a.name))))))) and
(xtype = 'pk'))>0 then '√' else '' end) 主鍵,
b.name 型別,
a.length 占用位元組數,
columnproperty(a.id,a.name,'precision') as 長度,
isnull(columnproperty(a.id,a.name,'scale'),0) as 小數字數,
(case when a.isnullable=1 then '√'else '' end) 允許空,
isnull(e.text,'') 預設值,
isnull(g.[value],'') as 字段說明
from syscolumns a left join systypes b
on a.xtype=b.xusertype
inner join sysobjects d
on a.id=d.id and d.xtype='u' and d.name<>'dtproperties'
left join syscomments e
on a.cdefault=e.id
left join sysproperties g
on a.id=g.id and a.colid = g.**allid
order by a.id,a.colorder
另外方法1:
select * from information_schema.tables
select * from information_schema.columns
另外方法2:
use 你的資料庫名
select * from sysobjects where xtype='u' and status>0
2：
select * from syscolumns where id =object_id('表名')
另外方法3:
exec sp_help
exec sp_tables
再來兩個比較好看的.
--查使用者表
select name from sysobjects where xtype='u' and status >0 order by name
--查出指定表名的字段資訊
select a.name from syscolumns a,sysobjects b where a.id=b.id and b.name=表名
order by a.name
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