python 去掉list中的重複元素

def f1(seq): 

# not order preserving 
set = {} 
map(set.__setitem__, seq, ) 
return set.keys()
def f2(seq): 
# order preserving 
checked = 
for e in seq: 
if e not in checked: 
return checked
def f3(seq): 
# not order preserving 
keys = {} 
for e in seq: 
keys[e] = 1 
return keys.keys()
def f4(seq): 
# order preserving 
nodupes = 
return nodupes
def f5(seq, idfun=none): 
# order preserving 
if idfun is none: 
def idfun(x): return x 
seen = {} 
result = 
for item in seq: 
marker = idfun(item) 
# in old python versions: 
# if seen.has_key(marker) 
# but in new ones: 
if marker in seen: continue 
seen[marker] = 1 
return result
def f6(seq): 
# not order preserving 
set = set(seq) 
return list(set)

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