山東大學資料庫實驗六2015最新版

2021-07-02 07:01:35 字數 3204 閱讀 8413

1.create view test6_01 as select sid,name,dname from pub.student where age<20 and dname='物理學院'order by sid

select * from test6_01

2.create view test6_02(sid,name,sum_score)

as (select pub.student.sid,name,sum(score)

from pub.student,pub.student_course

where pub.student.sid=pub.student_course.sid

and dname='軟體學院'

and class=2009

group by pub.student.sid,name)

select * from test6_02

3.create view test6_03 as(

select pub.student.sid,pub.student.name,score

from pub.student,pub.student_course,pub.course

where pub.student.sid=pub.student_course.sid

and pub.student_course.cid=pub.course.cid

and class=2010

and dname='電腦科學與技術學院'

and pub.course.name='作業系統')

select * fromm test6_03

4.create view test6_04 as

(select pub.student.sid,pub.student.name

from pub.student_course,pub.student,pub.course

where pub.student_course.sid=pub.student.sid

and pub.student_course.cid=pub.course.cid

and pub.course.name ='資料庫系統'

and score>90)

select * from test6_04

5.create view test6_05 as

(select pub.student.sid,pub.student_course.cid,pub.course.name,score

from pub.student,pub.student_course,pub.course

where pub.student_course.sid=pub.student.sid

and pub.student_course.cid=pub.course.cid

and pub.student.name='李龍'

)6.create view test6_06 as(

select pub.student.sid,name

from pub.student

where not exists(

(select cid

from pub.course)

minus(

select cid

from pub.student_course

where pub.student_course.sid=pub.student.sid)))

7.create view test6_07 as

(select sid,name

from pub.student

where sid in(

select sid

from pub.student_course

where score>=60)

and not exists((

select cid

from pub.course)

minus(select cid

from pub.student_course)))

create view test6_07 as

(select sid,name

from test6_06 where sid in

(select distinct sid

from pub.student_course

where sid in(select sid

from test6_06) and score>60))//不知道前兩個尤其是第二個為什麼不行,第二個有15行資料錯誤,下面的才是正確答案

create view test6_07 as

select * from test6_06 where sid not in (

select distinct sid from pub.student_course where sid in(select sid from test6_06) and score<60)

8.create view test6_08 as

(select cid,name

from pub.course

where fcid in(

select cid

from pub.course

where credit=2))

9.create view test6_09(sid,name,sum_credit)as

(select pub.student.sid,pub.student.name,sum(credit)

from pub.student,pub.student_course,pub.course

where pub.student_course.sid=pub.student.sid

and pub.student_course.cid=pub.course.cid

and class=2010

and dname='化學與化工學院'

and score>=60

group by pub.student.sid,pub.student.name)

10.create view test6_10 as

(select cid,name

from pub.course

where fcid in(select cid

from pub.course

where fcid is not null))

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