hdu 5643 約瑟夫環加強版

2021-07-10 11:27:06 字數 2293 閱讀 2548

@(e acmer)

在比賽中竟然沒有除錯正確,把函式裡面分配的區域性變數來作為鍊錶的內容了顯然函式一結束這塊記憶體就被**了.

code:

#include 

#include

#include

#include

#include

#include

#include

#include

#include

#include

#include

#include

using

namespace

std;

typedef pair pii;

typedef

long

long ull;

typedef

long

long ll;

typedef

vector

vi;

#define xx first

#define yy second

#define rep(i, a, n) for (int i = a; i < n; i++)

#define sa(n) scanf("%d", &(n))

#define vep(c) for(decltype((c).begin()) it = (c).begin(); it != (c).end(); it++)

const

int mod = int(1e9) + 7, inf = 0x3fffffff, maxn = 1e5 + 12;

int cnt;

struct node *p;

void moves(int x)

}void get(int n)

p -> nexts = cur;

cur -> lasts = p;

p = cur;

return;

}void del(void)

int main(void)

*/for (int i = 1; i <= n - 1; i++)

printf(",%d\n", p -> v);

}return

0;}

觀察發現: f(

n,k)

=(f(

n−1,

k1)+

k2)%

n

code:

int ysf(int n, int k)
但是,回到本題,每一次拿的位置是遞增的,這裡的k1

=k2+

1 ,只需稍作改變即可.

int ysf(int n, int k)
ac_code:

#include 

#include

#include

#include

#include

#include

#include

#include

#include

#include

#include

#include

using

namespace

std;

typedef pair pii;

typedef

long

long ull;

typedef

long

long ll;

typedef

vector

vi;

#define xx first

#define yy second

#define rep(i, a, n) for (int i = a; i < n; i++)

#define sa(n) scanf("%d", &(n))

#define vep(c) for(decltype((c).begin()) it = (c).begin(); it != (c).end(); it++)

const

int mod = int(1e9) + 7, inf = 0x3fffffff, maxn = 1e5 + 12;

int fun(int n, int k)

int main(void)

return

0;}

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