#ifndef poker_h_
#define poker_h_
//suits: games any of the four sets of 13 playing cards
//(clubs, diamonds, hearts, and spades) in a standard deck,
//the members of which bear the same marks.
//紅桃 : h - heart 桃心(象形), 代表愛情
//黑桃 : s - spade 橄欖葉(象形), 代表和平
//方塊 : d - diamond 鑽石(形同意合), 代表財富
//梅花 : c - club 三葉草(象形), 代表幸運
#include #include #include #include #include using namespace std;
struct card
;class poker
; const string point[13] = ;
private:
card card[52];
static int num;
public:
poker();
void randompoker();
card& dealpoker();
};#endif
#include "poker.h"
int poker::num = 0;
poker::poker()
}void poker::randompoker()
}card& poker::dealpoker()
#include "poker.h"
void showblackjack(const card, int);
bool bustblackjack(const card, int);
void winblackjack(const card, const card, int);
int main()
cout << "【莊家】";
showblackjack(dealer, 1);
cout << endl;
cout << "【玩家】";
showblackjack(player, count);
cout << endl;
cout << "是否繼續發牌？（y發牌/n結束）： ";
char ch;
while (cin >> ch)
switch (ch)
cout << "再來一局？（c繼續/q退出）： ";
if (cin >> ch && ch == 'c')
cout << "【莊家】";
showblackjack(dealer, 1);
cout << endl;
cout << "【玩家】";
showblackjack(player, count);
cout << endl;
cout << "是否繼續發牌？（y發牌/n結束）： ";
continue;
} else if (ch == 'q')
break;
} system("pause");
return 0;
}void showblackjack(const card c, int n)
}bool bustblackjack(const card c, int n)
else if (c[i].point == "2")
else if (c[i].point == "3")
else if (c[i].point == "4")
else if (c[i].point == "5")
else if (c[i].point == "6")
else if (c[i].point == "7")
else if (c[i].point == "8")
else if (c[i].point == "9")
else if (c[i].point == "10")
else if (c[i].point == "j")
else if (c[i].point == "q")
else if (c[i].point == "k")
}if (count_c1 > 21)
return false;
}void winblackjack(const card c, const card d, int n)
else if (c[i].point == "2")
else if (c[i].point == "3")
else if (c[i].point == "4")
else if (c[i].point == "5")
else if (c[i].point == "6")
else if (c[i].point == "7")
else if (c[i].point == "8")
else if (c[i].point == "9")
else if (c[i].point == "10")
else if (c[i].point == "j")
else if (c[i].point == "q")
else if (c[i].point == "k")
if (d[i].point == "a")
else if (d[i].point == "2")
else if (d[i].point == "3")
else if (d[i].point == "4")
else if (d[i].point == "5")
else if (d[i].point == "6")
else if (d[i].point == "7")
else if (d[i].point == "8")
else if (d[i].point == "9")
else if (d[i].point == "10")
else if (d[i].point == "j")
else if (d[i].point == "q")
else if (d[i].point == "k")
}if (count_c1 < count_c2 && count_c2 <= 21)
count_c1 = count_c2;
if (count_d1 < count_d2 && count_d2 <= 21)
count_d1 = count_d2;
if (count_c1 > 21)
else if (count_c1 >= count_d1)
else if (count_c1 < count_d1)
}
Unity乙個點繞另乙個點旋轉
引數 vector3 point 要旋轉的點 vector3 pivot 中心點 vector3 euler 旋轉的角度 函式 quaternion.euler float x,float y,float z 返回乙個繞z軸旋轉z度 圍繞x軸旋轉x度 圍繞y軸旋轉y度的旋轉。另乙個過載函式quate...
配置乙個Struts2 1 程式
首先第一步，用myeclipse建立乙個web專案 color green 引入基本的jar包，這些包可以在struts目錄下的空專案中找到 color img color green 引入struts.xml配置檔案，從那個示例空專案中複製黏貼，放在src目錄下 color color green...
2 1 開始乙個專案 功能梳理
專案名稱 部落格 blog 專案需求 3.管理員後台 管理使用者等一系列功能 專案梳理 按照atm的設計思路 user頻道功能需求 1.登陸註冊找回密碼等一系列相關的功能 2.文章的增刪改查等功能 頻道梳理 登陸註冊作為module進行設計，命名為account 文章管理也作為module進行設計，...