15位身份證號公升級為18位的SQL語句

2021-08-29 11:08:25 字數 1841 閱讀 9935

update 員工表 set 身份證號=

substring(身份證號,1,6)+'18'+substring(身份證號,7,9)+

substring('10x98765432',

(cast(substring(身份證號, 1,1) as int)*7

+cast(substring(身份證號, 2,1) as int)*9

+cast(substring(身份證號, 3,1) as int)*10

+cast(substring(身份證號, 4,1) as int)*5

+cast(substring(身份證號, 5,1) as int)*8

+cast(substring(身份證號, 6,1) as int)*4

+1*2

+8*1

+cast(substring(身份證號, 7,1) as int)*6

+cast(substring(身份證號, 8,1) as int)*3

+cast(substring(身份證號, 9,1) as int)*7

+cast(substring(身份證號,10,1) as int)*9

+cast(substring(身份證號,11,1) as int)*10

+cast(substring(身份證號,12,1) as int)*5

+cast(substring(身份證號,13,1) as int)*8

+cast(substring(身份證號,14,1) as int)*4

+cast(substring(身份證號,15,1) as int)*2

)% 11 + 1, 1)

where len(身份證號)=15 and substring(身份證號,13,3) in ('999','998','997','996')

-- 15位身份證號公升級為18位,適用於19xx年出生的公民

update 員工表 set 身份證號=

substring(身份證號,1,6)+'19'+substring(身份證號,7,9)+

substring('10x98765432',

(cast(substring(身份證號, 1,1) as int)*7

+cast(substring(身份證號, 2,1) as int)*9

+cast(substring(身份證號, 3,1) as int)*10

+cast(substring(身份證號, 4,1) as int)*5

+cast(substring(身份證號, 5,1) as int)*8

+cast(substring(身份證號, 6,1) as int)*4

+1*2

+9*1

+cast(substring(身份證號, 7,1) as int)*6

+cast(substring(身份證號, 8,1) as int)*3

+cast(substring(身份證號, 9,1) as int)*7

+cast(substring(身份證號,10,1) as int)*9

+cast(substring(身份證號,11,1) as int)*10

+cast(substring(身份證號,12,1) as int)*5

+cast(substring(身份證號,13,1) as int)*8

+cast(substring(身份證號,14,1) as int)*4

+cast(substring(身份證號,15,1) as int)*2

)% 11 + 1, 1)

where len(身份證號)=15 and substring(身份證號,13,3) not in ('999','998','997','996')

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