cookbook之字串匹配和搜尋

參考

import datetime

text =
'yao, yao, qie ke nao, jian bing guo zi, yao, lai, yi, tao, '
print(text.find(
'tao'
))#會返回第一次匹配到元素的下標
text2 = datetime.date.today(
)#顯示當前的年月日
text2 = str(text2)
print(type(text2))
print(text2)
import re
text1 =
'11/27/2012'
if re.match(r'\d+\-\d+\-\d+',text2):#原始字串
print(
'ok'
)else:
print(
"no"
)text =
'today is 11/27/2012. pycon starts 3/13/2013.'
a = re.findall(r'\d+/\d+/\d+',text)
print(a)
b = re.findall(r'(\d+)/(\d+)/(\d+)', text)
print(b)
#元組的形式
print(
'-----------------------'
)#使用迭代的方式展示
for m in re.finditer(r'(\d+)/(\d+)/(\d+)', text):
print(m.group(0))
print(m.group(1))
print(m.group(2))
print(m.group(3))
print(m.groups(
)) print(
'+++++++'
)test
= re.compile(r'(\d+)/(\d+)/(\d+)$'
)print(test.match(
'11/27/2012abcdef'
))print(test.match(
'11/27/2012'
).group(0))

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