**
已知煉表頭節點指標head，將鍊錶逆序。（不可申請額外空間）
#include
struct listnode
//建構函式};
class
solution
~solution()
listnode*
reverselist
(listnode* head)
return new_head;
//返回新煉表頭節點
//method-2 recursive solution, time:o(n) and space: o(n)
/* if (head == nullptr || head->next == nullptr)
listnode* p = reverselist(head->next);
head->next->next = head;
head->next = nullptr;
return p;*/}
};intmain()
head = solve.
reverselist
(&a)
;printf
("after reverse:\n");
while
(head)
return0;
}
before reverse:12
345after reverse:54
321**輸入乙個鍊錶，反轉鍊錶後，輸出新鍊錶的表頭
# -*-coding:utf-8-*-
class
listnode
:def
__init__
(self, x)
: self.val = x
self.
next
=none
class
solution
:def
reverselist
(self, phead)
:if phead ==
none
:return
none
if phead.
next
==none
:return phead
leftpointer = phead
midpointer = phead.
next
rightpointer = phead.
next
.next
leftpointer.
next
=none
while rightpointer !=
none
: midpointer.
next
= leftpointer
leftpointer = midpointer
midpointer = rightpointer
rightpointer = rightpointer.
next
midpointer.
next
= leftpointer
return midpointer
if __name__ ==
'__main__'
: l1 = listnode(1)
l2 = listnode(2)
l3 = listnode(3)
l4 = listnode(4)
l5 = listnode(5)
l1.next
= l2
l2.next
= l3
l3.next
= l4
l4.next
= l5
s = solution(
) r1=s.reverselist(l1)
while r1:
print
(r1.val)
r1=r1.
next
543
21
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