C 實現的簡易字串類

2021-10-05 17:57:40 字數 3886 閱讀 5032

c++ 實現的簡易字串類

#include


using


namespace std;


class


sstring


// 構造字元全部為ch，長度為count的字串


sstring


(const


char ch,


int count)


this


->m_ptrstr[


this


->m_nlength]


='\0';}


// 刪除所有字元chchar


bool


strdeletecharall


(const


char chchar)}if


(k ==


this


->m_nlength)


else


}// 刪除指定字元chchar


bool


strdeletechar


(const


char chchar)


this


->m_nlength -=1


;return


true;}


}return


false;}


// 建構函式


sstring


(const


char


* ptrstr)


this


->m_nlength = ptrstr - ptrtemp -1;


this


->m_ptrstr =


newchar


[this


->m_nlength +1]


;memset


(this


->m_ptrstr,0,


(this


->m_nlength +1)


*sizeof


(char))


;memcpy_s


(this


->m_ptrstr,


this


->m_nlength +


1, ptrtemp, ptrstr - ptrtemp);}


// 拷貝建構函式


sstring


(const sstring& str)


// 返回字串長度


intstrlength()


const


// 析構函式，用於釋放m_ptrstr動態分配的記憶體


virtual


~sstring()


this


->m_ptrstr =


null


;this


->m_nlength =0;


}// 刪除字串中[nleft,nright)的字元,nleft必須小於nright並且nright必須大於1


// 如果nleft小於1，則刪除[1,nright),如果nright>strlength,則刪除[nleft,strlength)


bool


deletebetween


(int nleft,


int nright)


if(nleft <=0)


if(nright >


this


->m_nlength +1)


int between = nright - nleft;


while


(nleft <=


this


->m_nlength)


this


->m_nlength -


= between;


return


true;}


// 擷取從npos開始的字元到npos+ncount的子串


const sstring&


substring


(int npos,


int ncount)


if(ncount >


(this


->m_nlength - npos +1)


|| ncount <0)


sstring* ptrsubstring =


newsstring()


; ptrsubstring-


>m_nlength =0;


ptrsubstring-


>m_ptrstr =


newchar


[ncount +1]


;memset


(ptrsubstring-


>m_ptrstr,


0, ncount +1)


;memcpy_s


(ptrsubstring-


>m_ptrstr, ncount,


this


->m_ptrstr + npos -


1, ncount)


; ptrsubstring-


>m_ptrstr[ncount]=0


; ptrsubstring-


>m_nlength = ncount;


return


*ptrsubstring;


}// 刪除指定位置的字元


bool


deleteposchar


(int i)


while


(i <=


this


->m_nlength)


this


->m_nlength -=1


;return


true;}


// 清空


void


strclear()


this


->m_nlength =0;


}// 銷毀字串


void


destory()


this


->m_nlength =0;


this


->m_ptrstr =


null;}


bool


strempty()


const


// 賦值運算子過載


const sstring&


operator=(


const sstring& str)


// 將字串str拼接到當前字串中


const sstring&


operator+(


const sstring& str)


this


->m_ptrstr = ptrtempstr;


this


->m_nlength = nsize -1;


return


*this;}


catch(.


..)}


// 獲取字串中第i個字元，i從0開始


char


operator


(int i)


const


const


char


*strdata()


const


// 查詢模式串substring與當前串的子串匹配所在的位置,-1表示不存在


intfindsubstring


(const sstring& substring)


const


else}if


(ptrnextvalue !=


null)if


(j > substring.m_nlength)


else


}protected


:// 獲取匹配陣列即nextval


void


getnextvalue


(int


*& ptrnextval)


const


else


}else}}


private


:char


* m_ptrstr;


int m_nlength;};


intmain


(void


)

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