rust增刪改查 v1 0 1

檔名稱

版本號作者

qq元件版本

rust增刪改查

v1.0.1

學生宮布

8416837

rust 1.44.1

mysql_async = "0.22.2"等步驟

依賴

[dependencies]

rand =
"0.3.17"
mysql =
"*"

extern crate rand;

use mysql::*
;use mysql:
:prelude:
:queryable;
use rand:
:rng;
#[derive
(debug, partialeq, eq)
]struct payment 
fn gen_db_conn
(conn: pooledconn)
fn main()
; let mut conn = match pool.
get_conn()
; let mut rng = rand:
:thread_rng()
;// let's create a table for payments.
let mut ret = conn.
query_drop
( r"create temporary table payment (
customer_id int not null,
amount int not null,
account_name text
)");// 建立臨時表，釋放連線時刪除或自定義刪除時機
// )")?;
println!
("建立臨時表："
, ret)
; let payments = vec!
[ payment 
, payment 
, payment 
, payment 
, payment ,]
;// now let's insert payments to the database
ret = conn.
exec_batch
( r"insert into payment (customer_id, amount, account_name)
values (
:customer_id,
:amount,
:account_name)",
payments.
iter()
.map
(|p| params!))
;// )?;
println!
("插入資料："
, ret)
;// let's select payments from database. type inference should do the trick here.
let selected_payments = conn
.query_map
("select customer_id, amount, account_name from payment",|
(customer_id, amount, account_name)|}
,);// )?;
// let's make sure, that `payments` equals to `selected_payments`.
// mysql gives no guaranties on order of returned rows 不保證返回順序
// without `order by`, so assume we are lucky. 如果不排序，那就看看運氣
// assert_eq!(payments, selected_payments); // 報錯：can't compare `std::vec::vec` with `std::result::result, mysql::error::error>`
println!
("查詢："
, selected_payments)
; println!
("~~~完成~~~");
}

建立臨時表：ok((),

)插入資料：ok((),
)查詢：ok(
[ payment ,
payment ,
payment ,
payment ,
payment ,
],)~~~完成~~~

use mysql::*

;use mysql:
:prelude:
:queryable;
#[derive
(debug, partialeq, eq)
]struct user 
fn main()
; let mut conn = match pool.
get_conn()
;// println!("", conn)
let selected_users = conn
.query_map
("select username,password, name from sys_user order by gmt_modified asc limit 1",|
(username, password, name)|}
,); println!
("查詢結果："
, selected_users)
;}

查詢結果：ok([

user ,]
,)

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