626 矩形重疊

2022-02-14 21:50:45 字數 1113 閱讀 5030

中文english

給定兩個矩形,判斷這兩個矩形是否有重疊。

樣例 1:

輸入 : l1 = [0, 8], r1 = [8, 0], l2 = [6, 6], r2 = [10, 0]

輸出 : true

樣例 2:

輸入 : [0, 8], r1 = [8, 0], l2 = [9, 6], r2 = [10, 0]

輸出 : false

l1代表第乙個矩形的左上角

r1代表第乙個矩形的右下角

l2代表第二個矩形的左上角

r2代表第二個矩形的右下角

保證:l1 != r1 並且 l2 != r2

"""

definition for

a point.

class

point:

def __init__(self, a=0, b=0

): self.x =a

self.y =b

"""class

solution:

""" @param l1: top-left coordinate of first rectangle

@param r1: bottom-right coordinate of first rectangle

@param l2: top-left coordinate of second rectangle

@param r2: bottom-right coordinate of second rectangle

@return:

true

if they are overlap or false

"""def dooverlap(self, l1, r1, l2, r2):

# write your code here

#滿足4個邊界點均小於或者大於的時候,找到4個不重疊的情況

if (r1.x < l2.x) or (l1.y < r2.y) or (r2.x < l1.x) or (l2.y return

false

return true

矩形法 矩形重疊

問題一 矩形以列表 x1,y1,x2,y2 的形式表示,其中 x1,y1 為左下角的座標,x2,y2 是右上角的座標。如果相交的面積為正,則稱兩矩形重疊。需要明確的是,只在角或邊接觸的兩個矩形不構成重疊。給出兩個矩形,判斷它們是否重疊並返回結果。示例 1 輸入 rec1 0,0,2,2 rec2 1...

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矩形重疊檢測。

矩形重疊型別注釋 corner overlap anchor overlap same width overlap inside overlap cross overlap typedef enum em rectoverlaptype em rectoverlaptype 判斷rect重疊的型別,...