客戶需求這樣的結果，還要求可以按要求時間（t1）查詢：
建立的資料表如下(table_1)：
資料如下：
怎樣才能把 table_1 這樣的資料變成 t1這樣的如下sql
步驟如下：
1. 把當天不需要的資料去掉：如下：
2. 時間序列與房間的列表，這樣規定的時間內所有的資料都為0
select *,0 as cb from(
select distinct rooms from table_1) as a1,(
select stuff(stuff(convert(char(8),dateadd(day,id-1,@begindays),112),5,0,n'-'),8,0,n'-')+n'' as times from @b) as a2
3. 再和時間序列並在一起（這樣每一天的資料都有了）
4.進行行列變換
declare @begindays datetime
set @begindays = '2013-07-01'
declare @enddays datetime
set @enddays = '2013-08-01'
declare @days int;
set @days = datediff(day,@begindays,@enddays);
declare @rooms varchar(50);
set @rooms = 'a4-09-01';
declare @sql nvarchar(max);
set @sql = 'declare @b table(id int identity,a int default 0); ';
set @sql = @sql +'insert @b select top 100 0 from syscolumns s ;';
set @sql = @sql+ ' declare @begindays datetime;';
set @sql = @sql+ ' set @begindays = '''+stuff(stuff(convert(char(8),@begindays,112),5,0,n'-'),8,0,n'-')+'''';
set @sql = @sql+ ' declare @enddays datetime;';
set @sql = @sql+ ' set @enddays = '''+stuff(stuff(convert(char(8),@enddays,112),5,0,n'-'),8,0,n'-')+'''';
set @sql = @sql+ ' declare @days int;';
set @sql = @sql+ ' set @days = datediff(day,@begindays,@enddays)';
set @sql = @sql+ ' declare @rooms varchar(50);';
set @sql = @sql+ ' set @rooms = '''+@rooms+'''';
set @sql= @sql +' select rooms ';
select @sql = @sql +' ,max(case when times = stuff(stuff(convert(char(8),dateadd(day,'''+cast (number as varchar(3))+'''-0,@begindays),112),5,0,''-''),8,0,''-'') then cb else 0 end) as '''+stuff(stuff(convert(char(8),dateadd(day, number ,@begindays),112),5,0,'-'),8,0,'-') +''''
from master..spt_values where [type] = 'p' and number
set @sql = @sql + 'from (
select rooms,times,max(cb) as cb from(
select rooms,times,0 as cb from(
select distinct rooms from table_1) as a1,(
select stuff(stuff(convert(char(8),dateadd(day,id-1,@begindays),112),5,0,''-''),8,0,''-'') as times from @b) as a2
union
select rooms,times,max(cb) as cb from(
select rooms,stuff(stuff(convert(char(8),max(times),112),5,0,''-''),8,0,''-'') as times,max(cb) as cb from table_1 where times > @begindays and times < @enddays group by rooms,times
) as t5 group by rooms,times
) as t6 group by rooms,times
) as tt1 group by rooms'
print (@sql)
print (len(@sql))
exec(@sql)
這樣就行成了最後的結查。
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