這個問題在論壇上被很多人問過，我這裡寫個函式，公開源**：
對應csdn論壇帖子為：
源**：
private declare function openprocess lib "kernel32.dll" (byval dwdesiredaccess as long, byval binherithandle as long, byval dwprocessid as long) as long
private declare function enumproces**odules lib "psapi.dll" (byval hprocess as long, byref lphmodule as long, byval cb as long, byref cbneeded as long) as long
private declare function getmodulefilenameexa lib "psapi.dll" (byval hprocess as long, byval hmodule as long, byval modulename as string, byval nsize as long) as long
private declare function closehandle lib "kernel32.dll" (byval hobject as long) as long
'根據程序號獲取程序路徑函式，原創：
function getprocesspathbyprocessid(pid as long) as string
on error goto z
dim cbneeded as long
dim szbuf(1 to 250) as long
dim ret as long
dim szpathname as string
dim nsize as long
dim hprocess as long
hprocess = openprocess(&h400 or &h10, 0, pid)
if hprocess <> 0 then
ret = enumproces**odules(hprocess, szbuf(1), 250, cbneeded)
if ret <> 0 then
szpathname = space(260)
nsize = 500
ret = getmodulefilenameexa(hprocess, szbuf(1), szpathname, nsize)
getprocesspathbyprocessid = left(szpathname, ret)
end if
end if
ret = closehandle(hprocess)
if getprocesspathbyprocessid = "" then
getprocesspathbyprocessid = "system"
end if
exit function
z:end function
'我的系統vb程序id為1716
'下面的結果顯示了vb程序的路徑為：d:/microsoft visual studio/vb98/vb6.exe
private sub ***mand1_click()
msgbox getprocesspathbyprocessid(1716)
end sub
'-------------------------------------------
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