Accelerated C 習題解答 第3章

部分習題參考了網上已有的解答

ex.3-0

#include#include#include#include#include#include#includeusing std::cin;

using std::cout;
using std::endl;
using std::string;
using std::vector;
using std::sort;
using std::streamsize;
using std::setprecision;
int main()
sort(homework.begin(),homework.end());
vec_sz mid = size/2;
double median;
median = size % 2 ==0 ? (homework[mid] + homework[mid-1]/2) : homework[mid];
streamsize prec =cout.precision();
cout <<"your final grade is " <
ex.3-1
中值是乙個可將數值集合劃分為相等的上下兩部分的數值。對於有限的數集，通過把所有的值高低排序後找出正中間的乙個作為中位數。中間點取決於所有的數值。
由此可知，如果任何乙個我們已經讀到的值被丟棄，則會改變原先中間點的位置，這樣就得不出準確的中值。 
,ex.3-2
#include#include#include#includeusing std::cin;
using std::cout;
using std::endl;
using std::vector;
using std::sort;
int main() 
}if (!found) 
}for (vec_sz i = 0; i < words.size(); ++i) 
getch();
return 0;
}

ex.3-4

#include#include#includeusing std::cin;

using std::cout;

using std::endl;

using std::string;

int main()

if (shortest_size == 0 || s.size() < shortest_size)

}cout <<"longest word is " << longest<<" (" <

ex.3-5

#include#include#include#include#include#includeusing std::cin;

using std::cout;

using std::endl;

using std::setprecision;

using std::string;

using std::streamsize;

using std::vector;

#define num_homework 2

int main()

double final_grade = 0.2 * midterm + 0.4 * final +0.4 * sum / count;

final_grades.push_back(final_grade);

cout <<"more? (y/n) ";

string s;

cin >> s;

if (s !="y")

done =true;

}for (vector::size_type i = 0; i

ex.3-6

#include#include#include#include#includeusing std::cin;

using std::cout;

using std::endl;

using std::setprecision;

using std::string;

using std::streamsize;

int main()

double homework_grade = (count > 0) ? sum / count: 0.0;

streamsize prec =cout.precision();

cout <<"your final grade is " <

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