django快速獲取專案所有的URL

django1.10快速獲取專案所有的url列表，可以用於許可權控制

函式如下：

import re

defget_url
(urllist , parent='' , depth=0 , url_list= , url_dict={}):
for entry in urllist:
url = entry.regex.pattern
if re.search('\(' , url) :
continue
#過濾正規表示式的url位址
url = url.replace(r'^' , '')
url = url.replace(r'$' , '')
url = url.replace(r'/' + '$' , '')
if depth == 0:
if url in ['admin' , 'admin/' , 'auth' , 'auth/']:
continue
if re.search('\/$' , url) :
else :
try :
except :
url_dict['/'] = 
else :
try :
except :
url_dict['/' + parent] = 
if hasattr(entry, 'url_patterns'):
get_url(entry.url_patterns , url , depth + 1)
# url_dict = 
# url_list = ['/basicdata/', '/basicdata/department/export', '/basicdata/department/list', '/basicdata/department/detail', '/basicdata/department/edit', '/login.html', '/index.html']
return url_dict

呼叫get_url函式獲得清單，必須使用函式或者class來封裝

def

recreate
(request):
from library.django.get_url import get_url
from lykops import urls
url_dict = get_url(urls.urlpatterns)
print(url_dict)
return httpresponseredirect(reverse('list'))

urlpatterns = [

......
url(r'^/recreate/', views.recreate, name="recreate"),
......
]

file "/opt/lykops/sysadmin/urls.py", line 5, in

file "/opt/lykops/sysadmin/views.py", line 76, in __init__
self.recreate()
file "/opt/lykops/sysadmin/views.py", line 79, in recreate
url_dict = get_allurl(urls.urlpatterns)
attributeerror: module 'lykops.urls' has no attribute 'urlpatterns'

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