JS Array類小總結

2021-08-29 17:47:49 字數 4674 閱讀 4821

array類:

首先 ^^

陣列定義習慣上都用 ,

下面分別使用 new array() 與

,驗證時間效率**如下,看看誰用的時間少:

var a = new date ;

var arr, direct, b = ;

for(var i=0; i<10000; i++)

arr = new array();

b.push(new date() - a);

a = new date;

for(var i=0; i<10000; i++)

direct = ;

b.push(new date() - a);

alert(b.join(" : "));

以下總結參考 js

高階程式設計

1 建立 array 類物件:

(1)	

var numbers= new array();//習慣上是var numbers= ;

numbers [0] = "one";

numbers [2] = "two";

numbers [3] = "three";

numbers [35] = "four";

alert(numbers [0]); //outputs 「one」

alert(numbers [35]); //outputs 」four」

alert(numbers.length); //outputs 「36」

(2)

var numbers= new array(15);// 習慣上是var numbers= [15];

alert(numbers [0]); //outputs "undefined"

alert(numbers.length); //outputs "15"

(3)

var numbers= new array("one","two","three");//習慣上是var numbers= ["one","two","three"];

alert(numbers [0]); //outputs "undefined"

numbers [10] = "four";

alert(numbers.length); //outputs "11"

(4)用字面量表示定義array物件:

var numbers= ["one","two","three"];

alert(numbers [0]); //outputs "undefined"

numbers [10] = "four";

alert(numbers.length); //outputs "11"

2  array 物件覆蓋 tostring() 方法和 valueof() 方法,返回字串。

var numbers= ["one","two","three"];

alert(numbers.tostring()); //outputs "one,two,three"

alert(numbers.valueof()); //outputs "one,two,three"

3  tolocalstring()

方法。

var numbers= ["one","two","three"];

alert(numbers.tolocalestring()); //outputs "one,two,three"

4  join()

方法,,用來連線字串的值。

var numbers= ["one","two","three"];

alert(numbers.join(",")); //outputs "one,two,three"

alert(numbers.join("-and-")); //outputs "one-and-two-and-three"

alert(numbers.join("")); //outputs "onetwothree"

alert(numbers.join(")(")); //outputs "one)(two)(three"

5  concat()

方法。

var numbers= ["one","two","three"];

var arr = numbers;

var numbers2=arr.concat("four","five");

alert(numbers2.tostring()); //outputs "one,two,three,four,five"

alert(numbers.tostring()); //outputs "one,two,three"

//alert(numbers.concat("four","five")); //outputs "one,two,three"

6  slice()

方法。

var numbers = ["one","two","three","four","five","six"];

var arr = numbers;

var numbers2 = arr.slice(1);

alert(numbers2.tostring()); //outputs "two,three,four,five,six"

var numbers3 = arr.slice(1,4);

alert(numbers3.tostring()); //outputs "two,three,four"

7 呼叫 push()

和 pop()

方法實現後進先出的結構(棧 stack

)。

var stack= ["one","two","three"];

stack.push("four");

stack.push("five","six");

alert(stack.tostring()); //outputs "two,three,four,five,six"

var removelast=stack.pop();

alert(removelast); //outputs "six"

var removelast=stack.pop();

alert(removelast); //outputs "five"

alert(stack.tostring()); //outputs "two,three,four"

8 呼叫 shift()

和 push()

方法實現後進後出結構(佇列 queue

)。

var queue= ["one","two","three"];

queue.push("four");

alert(queue.tostring()); //outputs "one,two,three,four"

var removefirst = queue.shift();

alert(removefirst); //outputs "one"

alert(queue.tostring()); //outputs "two,three,four"

9 其它。

(1)unshift()

方法把乙個項新增在陣列的第乙個位置。

(**的上面部分可以用 8

的**)

var addfirst = queue.unshift("one");

//alert(addfirst); //outputs "4"

alert(queue.tostring()); //outputs "one,two,three,four"

(2)reverse()

方法顛倒陣列項順序。

**銜接上面的 unshift()

queue.reverse(); 

alert(queue.tostring()); //outputs "four,three,two,one"

( 3 ) sort() 方法按陣列項的公升序排列。

var queue= ["one","two","three"];

queue.sort();

alert(queue.tostring()); //outputs "one,three,two"

( 4 ) splice() 方法。第一引數是指起始位置,第二個引數是要刪除項的個數,第三個引數是要插入的項。    

var queue= ["one","two","three","four","five"];

queue.splice(0,2);

alert(queue.tostring()); //outputs "three,four,five",delete one and two

queue.splice(1,1,"and1","and2","and3");

alert(queue.tostring()); //outputs "three,and1,and2,and3,four"

js array 物件方法總結

1.push 後增 push 向陣列的末尾新增乙個或多個元素,並返回新的長度 尾部新增 var a 1,2,3 var b a.push 4 console.log a 1,2,3,4 console.log b 4 2.unshift 前增 unshift 向陣列的開頭新增乙個或多個元素,並返回新...

js Array物件的常用方法總結

一 檢測陣列 array.isarray 確定某個值是不是陣列 var arr 1,2,3 array.isarray arr true二 轉換方法 1.tostring 返回由陣列中每個值的字串形式拼接而成的乙個以逗號分隔的字串 2.valueof 返回陣列本身 var colors red bl...

區間第k小類問題總結

剛碰到區間第k小的問題的時候只會區間sort,後來才掌握了一些解決此類問題的方法。區間第k小有的題目帶修改有的不帶修改,不論是什麼,都有對應的解決方法。1.我們可以分塊。分成根號n塊,塊內排序。對於每次查詢l,r我們二分答案 二分乙個值,統計區間內比他小的個數 對於不完整的區間,我們掃一遍統計,對於...