使用以下語句儲存乙個字串：
string = 『my moral standing is: 0.98765』
將其中的數字字串轉換成浮點數並輸出。
# -*- coding: utf-8 -*-
"""spyder editor
this is a temporary script file.
"""s =
"my moral standing is: 0.98765"
p =float
(s.split(
":")[1
])print
(p)
# -*- coding: utf-8 -*-
"""spyder editor
this is a temporary script file.
"""def
mv(s, flag, n):if
(n>
len(s)):
return-1
else:if
(flag==1)
:return s[n:
]+s[
:n]else
:return s[
-n:]
+s[:
-n]s,flag,n=
input
("please input s flag n"
).split(
)ans = mv(s,
int(flag)
,int
(n))
if(ans==-1
):print
("n's too large"
)else
:print
(ans)
[1, 0, 0, 1, 1, 0, 2, 2, 2, 0, 0, 0, 0, 1, 3, 1, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0]
"""
spyder editor
this is a temporary script file.
"""def
coalpha
(s):
lst =[0
]*26for w in
range
(len
(s)):if
(s[w]
>
'a')
and(s[w]
<
'z')
: lst[
ord(s[w])-
ord(
'a')]+=
1return lst
s =input
("please input s:"
)s = s.lower(
)print
(coalpha(s)
)
2 americano
4 mocha
# -*- coding: utf-8 -*-
"""spyder editor
this is a temporary script file.
"""def
pos(lis)
: cleaned_list =
for item in lis:
for key in item:
if key.isalpha()==
false
: item = item.replace(key,'')
return cleaned_list
coffee_list =
['32latte'
,'_americano30',,
'mocha35'
]cleaned = pos(coffee_list)i=1
for key in cleaned:
print
(i,key)
i+=1
測試資料：
enter the number: 6
螢幕輸出：
1,2,3,4,5,7,8,9,10,11
13,14,15,17,19,20,21,22,23,25
27,28,29,31,32,33,34,35,37,38
39,40,41,43,44,45,47,49,50,51
52,53,55,57,58,59,70,71,73,74
75,77,79,80,81,82,83,85,87,88
89,91,92,93,94,95,97,98,99,100
# -*- coding: utf-8 -*-
"""spyder editor
this is a temporary script file.
這裡為了保證輸出的10個數在同一行中不使用列表而使用字串型別
"""n =
int(
input
("please input n"))
#這裡再次注意輸入的為字串型別
num=
0#用於判斷個數
lis=
''for i in
range(1
,101):
if(i %
10==n)or(
(i//10)
%10==n)or(
(i//
100)%10
==n)
or(i % n==0)
:continue
lis+=
str(i)
num+=
1if num==10:
print
(lis)
lis=
'' num=
0else
: lis+=
','if num!=0:
print
(lis)
# -*- coding: utf-8 -*-
"""spyder editor
this is a temporary script file.
"""import random
with
open
('random.txt'
,'w+'
)as f:
for i in
range(1
,501):
f.write(
str(random.randint(1,
100)))
f.write(
'\n'
) f.seek(0)
ans=f.readlines(
)for key in ans:
key = key.strip(
)co =[0
]*120for key in ans:
co[int(key)]+=
1maxx=
-10000
ret=-1
for i in
range(1
,101):
if maxx < co[i]
: maxx = co[i]
ret=i
else
:continue
print
(ret)
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