select
count(1
)as total, date_format(created_time,
'%y-%m-%d'
)as days from task_execution group
by days desc
;
select
count(1
)as total, week(created_time)
as weeks from task_execution group
by weeks desc
;
select
count(1
)as total,
month
(created_time)
as months from task_execution group
by months desc
;
select
count(1
)as total,
year
(created_time)
as years from task_execution group
by years desc
;
注意:
date_add(createtime,interval 1 day) 得到指定日期後一天的日期/把1改為任意數字就可以得到後n天的日期
date_sub(createtime,interval 1 day) 得到指定日期前一天的日期/把1改為任意數字就可以得到前n天的日期
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