python爬蟲豆瓣高分電影前一百部

處理json

顯示採用jsonpath得到電影名

因為博主初學，還不會得到電影名與評分，故採取了兩次jsonpath.jsonpath

得到之後的list進行交叉合併，此處使用的是chain

在合併後的list採取演算法使其進行換行以及隔開

最後儲存在本地

import requests

import json
import jsonpath
from itertools import chain
url =
""headers =
r = requests.get(url=url,headers=headers)
# print(r.content.decode())
ret = json.dumps(r.content.decode(
),ensure_ascii=
false
,indent=4)
# print(type(r.content.decode()))
with
open
("douban.json"
,"w"
,encoding=
"utf-8"
)as f:
f.write(ret)
## with open("douban.json","r",encoding="utf-8") as f:
# ret4 = json.load(f)
# print(ret4)
# print(type(ret4))
# print(r.json())
# res = r.json()['subjects'][0]['title']
# print(r.json()['subjects'][0]['title'])
# print(type(res))
# print(r.json())
# print(type(r.json()))
name = jsonpath.jsonpath(r.json(),
'$..title'
)rate = jsonpath.jsonpath(r.json(),
'$..rate'
)# print(name)
# print(rate)
# print(type(name))
want =
list
(chain.from_iterable(
zip(name,rate)))
# print(want)
count1 =
0for w in want:
if count1%3==
1:want.insert(count1,
":")
# elif count%2 == 0:
# want.insert(count,"\n")
# print()
count1 +=
1count2 =
0for w in want:
if count2%4==
0:want.insert(count2,
"\n"
)# elif count%2 == 0:
# want.insert(count,"\n")
# print()
count2 +=
1print
(want)
str1 =
" ".join(want)
print
(str1)
with
open
("want.txt"
,"w"
,encoding=
"utf-8"
)as f:
f.write(str1)

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