乙個訂單表，已知時間字串，需要計算出兩筆訂單之間的時間差，並找出兩筆訂單中時間差最大的乙個
import datetime
time1 =
"20201222171220360"
time2 =
"20201222171320120"
time3 =
"20201222171400360"
time4 =
"20201222171400820"
time5 =
"20201222171500060"
t1 = datetime.datetime.strptime(time1,
"%y%m%d%h%m%s%f"
)#年月日時分秒微秒
t2 = datetime.datetime.strptime(time2,
"%y%m%d%h%m%s%f"
)t3 = datetime.datetime.strptime(time3,
"%y%m%d%h%m%s%f"
)t4 = datetime.datetime.strptime(time4,
"%y%m%d%h%m%s%f"
)t5 = datetime.datetime.strptime(time5,
"%y%m%d%h%m%s%f"
)diff1 = t2-t1
diff2 = t3-t2
diff3 = t4-t3
diff4 = t5-t4
time_list =[[
'diff1'
,diff1],[
'diff2'
,diff2],[
'diff3'
,diff3],[
'diff4'
,diff4]
]time_list.sort(key=
lambda ele:ele[1]
,reverse=
true
)#根據第二個元素排序
print
(t1)
print
(t2)
print
(t3)
print
(t4)
print
(t5)
print
(diff1)
print
(diff2)
print
(diff3)
print
(diff4)
print
(diff4.seconds, diff4.microseconds)
#列印時間差秒，微秒
print
(time_list)--
----
----
----
----
----
----
----
----
--2020-12
-2217:
12:20.360000
2020-12
-2217:
13:20.120000
2020-12
-2217:
14:00.360000
2020-12
-2217:
14:00.820000
2020-12
-2217:
15:00.0600000:
00:59.7600000:
00:40.2400000:
00:00.4600000:
00:59.240000
59240000[[
'diff1'
, datetime.timedelta(seconds=
59, microseconds=
760000)]
,['diff4'
, datetime.timedelta(seconds=
59, microseconds=
240000)]
,['diff2'
, datetime.timedelta(seconds=
40, microseconds=
240000)]
,['diff3'
, datetime.timedelta(microseconds=
460000)]
]
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