\[i = \arg \max _ p ( i | o ) = \arg \max _ \frac = \arg \max _ p ( o | i ) p ( i )
\]文本校錯
音字轉換
詞性標註
\[p ( s ) = p \left( w _ w _ \dots w _ \right) = p \left( w _ \right) p \left( w _ | w _ \right) p \left( w _ | w _ w _ \right) \ldots p \left( w _ | w _ w _ \dots w _ \right)
\]\[p \left( w _ | w _ w _ \dots w _ \right) = \frac w _ \ldots w _ \right) } w _ \dots w _ \right) }
\]\[p _ \left( w _ w _ , \ldots w _ \right) = \frac w _ \dots w _ \right) + 1 } , \left( b = | v | ^ \right)
\]\[\arg \max _ p ( x | o ) = \arg \max _ \frac = \arg \max _ p ( x , o )
\]\[\begin ( i ) = \pi _ b _ \left( o _ \right) } \\ ( i ) = 0 } \end
\]\[\begin ( j ) = \underset \max \delta _ ( i ) a _ b _ \left( o _ \right) } \\ ( j ) = \underset \delta _ ( i ) a _ b _ \left( o _ \right) } \end
\]\[\begin = \max _ \delta _ ( i ) } \\ ^ = \underset \delta _ ( i ) } \end
\]\[q _ ^ = \psi _ \left( q _ ^ \right) , \quad t = t - 1 , \ldots , 1
\]\[\delta _ ( 0 ) = 0.5*0.5=0.25
\]\[\delta _ ( 1 ) = 0.5*0.3=0.15
\]\[\delta _ ( 2 ) = 0*0.2=0
\]\[\delta _ ( 0 ) = max(0.25*0.3*0.3, 0, 0)=0.0225
\]\[\delta _ ( 1 ) =max(0.25*0.2*0.4, 0.15*0.4*0.4, 0)=0.024
\]\[\delta _ ( 2 ) = max(0.25*0.5*0.3, 0.15*0.6*0.3, 0)=0.0375
\]\[\delta _ ( 0 ) = max(0.0225*0.3*0.2, 0, 0)=0.00135
\]\[\delta _ ( 1 ) =max(0.0225*0.2*0.3, 0.024*0.4*0.3, 0)=0.00288
\]\[\delta _ ( 2 ) =max(0.0225*0.5*0.5, 0.024*0.6*0.5, 0)=0.0072
\]接著尋找上一步中生成該概率值（\(0.0072\)）的數作為前一步結果。
以此類推。
hmm的輸出字元集合：詞彙集合
\(\pi _ }\)：詞性標記\(t_i\)初始概率
\(a_\)：從詞性標記\(t_i\)到\(t_j\)的狀態轉移概率
\(b_\)：詞性標記\(t_j\)對應的詞\(w_k\)的發射概率
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