本文包含一些與日期相關的常見查詢。
希望使用者發現它有用。
1.確定乙個月中特定工作日的第一次和最後一次發生的日期
select next_day(trunc(sysdate,'mm')-1,'sunday') first_sunday, next_day(last_day(trunc(sysdate,'mm'))-7,'sunday') last_sunday from dual
2.確定乙個月的第一天和最後一天
select trunc(sysdate,'mm') firstday,
last_day(sysdate) lastday from dual
select to_number(to_char(sysdate,'hh24')) hour,
to_number(to_char(sysdate,'mi')) min,
to_number(to_char(sysdate,'ss')) sec,
to_number(to_char(sysdate,'dd')) day,
to_number(to_char(sysdate,'mm')) mth,
to_number(to_char(sysdate,'yyyy')) year
from dual
select add_months(trunc(sysdate,'y'),12) - trunc(sysdate,'y') from dual
select decode(to_char(last_day(add_months(trunc(sysdate,'y'),1)),'dd'),28 ,'not a leap year','leap year') from dual
select rownum qtr,
add_months(trunc(sysdate,'y'),(rownum-1)*3) q_start, add_months(trunc(sysdate,'y'),rownum*3)-1 q_end from emp where rownum <= 4
select e.hiredate from
(select dense_rank() over (order by hiredate desc)n,hiredate
from emp )e where e.n<=3
select months_between(max_hd,min_hd) months,
months_between(max_hd,min_hd)/12 years
from (select min(hiredate) min_hd, max(hiredate) max_hd from emp ) x
select dy*24 as hr, dy*24*60 as min, dy*24*60*60 as sec from (select (max(case when ename = 'ward' then hiredate end) -
max(case when ename = 'allen' then hiredate end)) as dy from emp) x
select ename, hiredate, next_hd,
next_hd - hiredate diff from (
select deptno, ename, hiredate, lead(hiredate)over(order by hiredate) next_hd
from emp) order by hiredate
with x as ( select level lvl from dual connect by level <= ( add_months(trunc(sysdate,'y'),12)-trunc(sysdate,'y'))
) select to_char(trunc(sysdate,'y')+lvl-1,'day'), count(*) from x group by to_char(trunc(sysdate,'y')+lvl-1,'day')
from:
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