二叉樹的實現

2021-08-20 19:18:27 字數 2098 閱讀 3742

實現二叉樹的基本操作:建立、遍歷、計算深度、結點數、葉子數等。

輸入c,先序建立二叉樹,#表示空節點;

輸入h:計算二叉樹的高度;

輸入l:計算二叉樹的葉子個數;

輸入n:計算二叉樹節點總個數;

輸入1:先序遍歷二叉樹;

輸入2:中序遍歷二叉樹;

輸入3:後續遍歷二叉樹;

輸入f:查詢值=x的節點的個數;

輸入p:以縮格文字形式輸出所有節點

#include

//#include "bintree.h"

#include

//#include "cstdio"

#include

using namespace std;

class tree;

class treenode;

treenode(char data1):data(data1),left(null),right(null){}

};class tree

tree(char end1,treenode *p=

null) :root(p),endtag(end1){}

~tree()

bool isempty()

treenode *left(treenode *subtree)

treenode *right(treenode *subtree)

treenode *getroot()

void createtree()

void inorder()

void preorder()

void postorder()

treenode *

parent(treenode *current)

int size ()

int height()

int leaf()

int find1(char &x)

void print()

};int tree::size(treenode *subtree)

void tree::createtree(treenode *&subtree)

}void tree::destroy(treenode *&subtree)

}void tree::inorder(treenode *subtree)

}void tree::preorder(treenode *subtree)

}void tree::postorder(treenode *subtree)

}treenode *tree::parent(treenode *subtree,treenode *current)

else

return

parent(subtree->right,current);

}int tree::height(treenode *subtree)

int tree::leaf(treenode *subtree)

int tree::find1(char &x,treenode *subtree)

void tree::print(treenode *subtree,int layer)

}using namespace std;

int main()

else

if(a==

'h')

cout<<

"height="

<"."

if(a==

'l')

cout<<

"leaf="

<"."

if(a==

'n')

cout<<

"nodes="

<"."

if(a==

'1')

else

if(a==

'2')

else

if(a==

'3')

else

if(a==

'f')

else

if(a==

'p')

}return

0;}

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