hdu3662 三維凸包的面的個數

#include#include#include#includeusing namespace std;

#define n 600
#define eps 1e-8
struct tpoint
tpoint(double _x,double _y,double _z):x(_x),y(_y),z(_z){}
tpoint operator-(const tpoint p)
tpoint operator *(const tpoint p)
double operator ^(const tpoint p) };
struct fac
;struct t3dhull
//三角形面積 *2 
double area(tpoint a,tpoint b,tpoint c)
//四面體有向體積*6 
double volume(tpoint a,tpoint b,tpoint c,tpoint d)
//正：點在面的銅像 
double ptoplane(tpoint &p,fac &f)
void deal(int p,int a,int b)
}} void dfs(int p,int cnt)
void construct()
}if(tmp)return;
tmp=true;
for(i=2;ieps)
}if(tmp)return;
tmp=true;
for(i=3;ieps)
}if(tmp)return;
fac add;
for(i=0;i<4;i++)
for(i=4;ieps)
}} int cnt=********cnt;
********cnt=0;
for(i=0;i}
double area()
//判斷s與t是否是同乙個面
/*因為凸包是由n個三角形組成的，所以要判斷有多少個面就要重複的三角形，用面積判斷*/ 
bool same(int s, int t)
//統計面的個數 
int coun()
}couns+=nb;
} return couns;
}}hull;
int main()
return 0;
}

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